K^(2/5)=0.125

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Solution for K^(2/5)=0.125 equation: 


K in (-oo:+oo)

K^(2/5) = 0.125 // - 0.125

K^(2/5)-0.125 = 0

1*K^(2/5) = 0.125 // : 1

K^(2/5) = 0.125

K^(2/5) = 0.125 // ^ 5

K^2 = 0.125^5 // ^ 1/2

abs(K) = 0.125^(5/2)

K = 0.125^(5/2) or K = -0.125^(5/2)

K in { 0.125^(5/2), -0.125^(5/2) }

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